3x^2/4=3600

Solution for 3x^2/4=3600 equation:

3x^2/4=3600

We move all terms to the left:

3x^2/4-(3600)=0

We multiply all the terms by the denominator


3x^2-3600*4=0

We add all the numbers together, and all the variables

3x^2-14400=0

a = 3; b = 0; c = -14400;
Δ = b2-4ac
Δ = 02-4·3·(-14400)
Δ = 172800
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

The end solution:

$\sqrt{\Delta}=\sqrt{172800}=\sqrt{57600*3}=\sqrt{57600}*\sqrt{3}=240\sqrt{3}$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(0)-240\sqrt{3}}{2*3}=\frac{0-240\sqrt{3}}{6}
=-\frac{240\sqrt{3}}{6}
=-40\sqrt{3}
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(0)+240\sqrt{3}}{2*3}=\frac{0+240\sqrt{3}}{6}
=\frac{240\sqrt{3}}{6}
=40\sqrt{3}
$